最佳答案
回答者:老王 回答时间:2008/02/24
从publish 表中取出第 n 条到第 m 条的记录:
SELECT TOP m-n+1 *
FROM publish
WHERE (id NOT IN
(SELECT TOP n-1 id
FROM publish))
id 为publish 表的关键字
SELECT TOP m-n+1 *
FROM publish
WHERE (id NOT IN
(SELECT TOP n-1 id
FROM publish))
id 为publish 表的关键字


